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День в году



 
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inna
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PostPosted: Wed Feb 25, 2009 2:54 pm    Post subject: День в году Reply with quote
Не подскажете: какая функция может вернуть порядковый номер дня в году? Embarassed Или нет такой?
Спасибо!
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ghost
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PostPosted: Wed Feb 25, 2009 3:07 pm    Post subject: Reply with quote
ну например ФМ 'FI_PSO_FULL_DAY_MONTH_YEAR_GET'
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Удав
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PostPosted: Wed Feb 25, 2009 3:49 pm    Post subject: Reply with quote
Поищите здесь Wink
А вообще можно и по другому:
Code:

REPORT  z_calc_date.

PARAMETERS: p_date TYPE sy-datum DEFAULT sy-datum.

DATA: first_date TYPE sy-datum,
      days TYPE i.

START-OF-SELECTION.
  first_date = p_date.
  first_date+4(4) = '0101'.

  CALL FUNCTION 'DAYS_BETWEEN_TWO_DATES'
    EXPORTING
      i_datum_bis                   = p_date
      i_datum_von                   = first_date
*     I_KZ_EXCL_VON                 = '0'
     i_kz_incl_bis                 = '1'
*     I_KZ_ULT_BIS                  = ' '
*     I_KZ_ULT_VON                  = ' '
*     I_STGMETH                     = '0'
*     I_SZBMETH                     = '1'
   IMPORTING
     e_tage                        = days
   EXCEPTIONS
     days_method_not_defined       = 1
     OTHERS                        = 2.
  IF sy-subrc <> 0.
* MESSAGE ID SY-MSGID TYPE SY-MSGTY NUMBER SY-MSGNO
*         WITH SY-MSGV1 SY-MSGV2 SY-MSGV3 SY-MSGV4.
  ENDIF.
  WRITE: / p_date, '-', first_date, '=', days.

  WRITE: / 'Direct calc'.
  days = p_date - first_date.
  WRITE: / p_date, '-', first_date, '=', days.
[/code]
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С уважением,
Удав.
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inna
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Joined: 25 Mar 2008
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PostPosted: Wed Feb 25, 2009 5:02 pm    Post subject: Reply with quote
Спасибо! 'FI_PSO_FULL_DAY_MONTH_YEAR_GET' сработала, остальное не пробовала Smile
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DKiyanov
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Location: Хабаровск
PostPosted: Thu Feb 26, 2009 3:33 am    Post subject: Reply with quote
Можно и без ФМсов обойтись
ABAP прекрасно вычисляет разницу между датами
пример:
Code:

data: d type d.
d(4) = sy-datum(4).
d+4(4) = '0101'.
x = sy-datum - d.
write: / x.
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