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Помогите найти ошибку SDOK_LOIO_PROPERTIES_SET



 
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Sed0Y
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PostPosted: Wed Jul 07, 2010 12:03 pm    Post subject: Помогите найти ошибку SDOK_LOIO_PROPERTIES_SET Reply with quote
Когда выполняю отчет вываливается дамб и пишет:
"Incorrect parameter with CALL FUNCTION.
This parameter was "OBJECT_ID"."

Но я не мог понять что не так

Code:
REPORT  ZBDSCHTB.

TABLES BDS_LOIO.

TYPES: BEGIN OF tabl,
    LO_CLASS  TYPE SDOK_LOCL,
    PROP01    TYPE SDOK_PRV_S,
    LOIO_ID   TYPE SDOK_LOID,
END OF tabl.

DATA:
      gt_dat TYPE TABLE OF tabl,
      wa_dat TYPE tabl.

START-OF-SELECTION.

  PERFORM GetData.

FORM GetData.

  DATA:
        p_lo_class  type sdok_locl,
        p_prop01    type sdok_prv_s,
        p_loio_id   type sdok_loid.

  data:
        it_prop type standard table of sdokpropty,
        wa_prop type sdokpropty.

  data:
        it_obj type standard table of sdokobject,
        wa_obj type sdokobject.

  SELECT * FROM BDS_LOIO INTO CORRESPONDING FIELDS OF TABLE gt_dat WHERE PROP01 <> ''.

  LOOP AT gt_dat INTO wa_dat.

    p_lo_class = wa_dat-LO_CLASS.
    p_loio_id  = wa_dat-LOIO_ID.
    p_prop01   = wa_dat-PROP01.

    TRANSLATE p_prop01 TO UPPER CASE.

    move 'DESCRIPTION' to wa_prop-name.
    move p_prop01      to wa_prop-value.
    append wa_prop to it_prop.

    move p_loio_id    to wa_obj-objid.
    move p_lo_class   to wa_obj-class.
    append wa_obj to it_obj.

    IF ( p_lo_class EQ 'BDS_LOC1' ) AND ( p_prop01 EQ 'INCOMING' OR p_prop01 EQ 'OUTGOING').
      CALL FUNCTION 'SDOK_LOIO_PROPERTIES_SET'
        IMPORTING
             OBJECT_ID               = it_obj
        TABLES
             PROPERTIES              = it_prop
        EXCEPTIONS
             NOT_EXISTING            = 1
             BAD_PROPERTIES          = 2
             NOT_AUTHORIZED          = 3
             EXCEPTION_IN_EXIT       = 4
             OTHERS                  = 5.
    ENDIF.
  ENDLOOP.
ENDFORM.
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vga
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PostPosted: Wed Jul 07, 2010 1:07 pm    Post subject: Reply with quote
Code:
REPORT  zbdschtb.

TABLES bds_loio.

TYPES: BEGIN OF tabl,
    lo_class  TYPE sdok_locl,
    prop01    TYPE sdok_prv_s,
    loio_id   TYPE sdok_loid,
END OF tabl.

DATA:
      gt_dat TYPE TABLE OF tabl,
      wa_dat TYPE tabl.

START-OF-SELECTION.

  PERFORM getdata.

*&---------------------------------------------------------------------*
*&      Form  GetData
*&---------------------------------------------------------------------*
*       text
*----------------------------------------------------------------------*
FORM getdata.

  DATA:
        p_lo_class  TYPE sdok_locl,
        p_prop01    TYPE sdok_prv_s,
        p_loio_id   TYPE sdok_loid.

  DATA:
        it_prop_tmp TYPE STANDARD TABLE OF sdokpropty,
        it_prop TYPE STANDARD TABLE OF sdokpropty,
        wa_prop TYPE sdokpropty.

  DATA:
        it_obj TYPE STANDARD TABLE OF sdokobject,
        wa_obj TYPE sdokobject.

  SELECT * FROM bds_loio INTO CORRESPONDING FIELDS OF TABLE gt_dat WHERE prop01 <> ''.

  LOOP AT gt_dat INTO wa_dat.

    p_lo_class = wa_dat-lo_class.
    p_loio_id  = wa_dat-loio_id.
    p_prop01   = wa_dat-prop01.

    TRANSLATE p_prop01 TO UPPER CASE.

    MOVE 'DESCRIPTION' TO wa_prop-name.
    MOVE p_prop01      TO wa_prop-value.
    APPEND wa_prop TO it_prop.

    MOVE p_loio_id    TO wa_obj-objid.
    MOVE p_lo_class   TO wa_obj-class.
*    append wa_obj to it_obj.

    IF ( p_lo_class EQ 'BDS_LOC1' ) AND ( p_prop01 EQ 'INCOMING' OR p_prop01 EQ 'OUTGOING').
      CALL FUNCTION 'SDOK_LOIO_PROPERTIES_SET'
*        IMPORTING
        EXPORTING
             object_id               = wa_obj
        TABLES
             properties              = it_prop_tmp
        EXCEPTIONS
             not_existing            = 1
             bad_properties          = 2
             not_authorized          = 3
             exception_in_exit       = 4
             OTHERS                  = 5.
      IF sy-subrc IS INITIAL.
        APPEND LINES OF it_prop_tmp TO it_prop.
      ENDIF.
    ENDIF.
  ENDLOOP.
ENDFORM.                    "GetData

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Sed0Y
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Age: 41
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PostPosted: Fri Jul 09, 2010 4:36 pm    Post subject: Reply with quote
О! Чуть переделал и все работает - Большое спасибо!
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