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Непонятки с SELECT SUM



 
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Gleb
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Joined: 18 Jan 2008
Posts: 32

PostPosted: Tue Oct 21, 2008 4:14 pm    Post subject: Непонятки с SELECT SUM Reply with quote

Здравствуйте, почему первый селект возвращает sy-subrc = 0, а второй sy-subrc = 4 ?

Code:
    DATA: l_netwr TYPE vbap-netwr.
    SELECT SUM( p~netwr ) INTO l_netwr
    FROM lips AS l
    JOIN likp AS k ON k~vbeln = l~vbeln
    JOIN vbuk AS u ON u~vbeln = l~vgbel
    JOIN vbap AS p ON p~vbeln = l~vgbel
                  AND p~posnr = l~vgpos
    WHERE k~fkdat LE pdate
      AND k~kunnr EQ itab_ua-kunnr
      AND u~wbstk EQ 'C'
      AND u~fkstk NE 'C'.



Code:
    DATA: l_netwr TYPE vbap-netwr,
     sum TYPE  vbap-netwr.
    SELECT p~netwr INTO l_netwr
    FROM lips AS l
    JOIN likp AS k ON k~vbeln = l~vbeln
    JOIN vbuk AS u ON u~vbeln = l~vgbel
    JOIN vbap AS p ON p~vbeln = l~vgbel
                  AND p~posnr = l~vgpos
    WHERE k~fkdat LE pdate
      AND k~kunnr EQ itab_ua-kunnr
      AND u~wbstk EQ 'C'
      AND u~fkstk NE 'C'.

      ADD l_netwr TO sum.

    ENDSELECT.
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Удав
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Age: 48
Joined: 25 Jan 2008
Posts: 580
Location: Москва

PostPosted: Wed Oct 22, 2008 2:43 pm    Post subject: Reply with quote

Для функций агрегации SY-SUBRC всегда 0 вне зависимости, есть в таблице данные, удовлетворяющие условиям, или нет. В этом случае нужно смотреть значение переменной, в которую происходит суммирование.
Для SELECT .. ENDSELECT SY-SUBRC = 4, потому что не нашлось ни одной записи по заданным условиям.

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